Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

is this vector field F tangent to or normal to the curve C

OpenStudy (anonymous):

F=<y,-x> where C={(x,y):x^2+y^2=1} and n=<x,y>

OpenStudy (anonymous):

n is a normal to C

OpenStudy (anonymous):

i think is tangent but i'm not sure

OpenStudy (anonymous):

Take the dot product of the normal vector and F: \[<y, -x>*<x,y>=xy-xy=0\]Since the vectors are orthogonal, the vector field cannot be normal to the curve (if it was, F and n would be parallel). Since your only other choice is parallel, they are parallel.

OpenStudy (anonymous):

I mean tangent...lol

OpenStudy (anonymous):

so its normal at all points to C?

OpenStudy (anonymous):

Another way to see this is to note that C is just a unit circle:|dw:1353383917635:dw|No, F is tangent to all point of C

OpenStudy (anonymous):

yea C is only circle and the vector F goes in circles so that means its tangent at all points on C?

OpenStudy (anonymous):

F is tangent because it is orthogonal to the normal vector n.

OpenStudy (anonymous):

|dw:1353384188503:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!