is this vector field F tangent to or normal to the curve C
F=<y,-x> where C={(x,y):x^2+y^2=1} and n=<x,y>
n is a normal to C
i think is tangent but i'm not sure
Take the dot product of the normal vector and F: \[<y, -x>*<x,y>=xy-xy=0\]Since the vectors are orthogonal, the vector field cannot be normal to the curve (if it was, F and n would be parallel). Since your only other choice is parallel, they are parallel.
I mean tangent...lol
so its normal at all points to C?
Another way to see this is to note that C is just a unit circle:|dw:1353383917635:dw|No, F is tangent to all point of C
yea C is only circle and the vector F goes in circles so that means its tangent at all points on C?
F is tangent because it is orthogonal to the normal vector n.
|dw:1353384188503:dw|
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