how do i find r in a geometric sequence?
1,1/3,1/9,1/27
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OpenStudy (anonymous):
Divide
2nd term / 1st term
Divide again to verify
3rd term / 2nd term
OpenStudy (anonymous):
ok well, first off, this isnt a geometric sequence right?
OpenStudy (anonymous):
since its not a common ratio
OpenStudy (anonymous):
3rd/2nd=2nd/1st=r
so to know it is geometric we must to devide
for arithmetic we have to minus
2nd terms -1st terms=n
OpenStudy (anonymous):
It is a GM
There is a common ratio
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OpenStudy (anonymous):
well i know that the 2nd term that when multiplied by 3 gives me the 3rd and when done once more gives me the third term, is that enough to say its a geometric sequence, its clear i dont know how to to do 1/3-1