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simplify 2log2(8x)
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Is that base-2? \[2 \log_{2}8x \]
yea
2log28x?
Okay. It's already fairly simplified, although you could get rid of the base-2. \[2 \log_{2}8x = \frac{2\log 8x}{\log 2}\]
16x?
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8x?
8?
log2(8x)?
Ummm... no. I'm not sure if you're trying to solve it or if you're suggesting those should go after the log.
idk its a multiple choice question ?
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Okay. Well, your answer will still have a log involved.
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