Question

how do you solve a complex numbers questions where z conjugate+2z = -4-4i+10+3i, where you want to solve for z

Answer 1

dY=dX + ZdX + XdZ-2*ZdZ. =(1+Z)dX + (X-2Z)dZ. 3.2) Y=40 + 3X + 4XZ. 2. dY=3dX + 4Z. 2. dX + 8XZdZ. = (3+4Z. 2 ). dX +8XZdZ. 3.3) For 3.1),

Answer 2

what is dY?

Answer 3

\[ \large \overline{z}+2z=-4-4i+10+3i=6-i \]

let \(z=a+ib\) so \(\overline{z}=a-ib\) then
\[ \large 6-i=\overline{z}+2z=(a-ib)+2(a+ib)=3a+ib \]
so \(3a=6\) and \(b=-1\) and from this \(a=2\) and \(b=-1\) therefore
\[ \large z=2-i \]

Answer 4

THANK YOU SO MUCH