Prove that there is no smallest positive real number?
I can divide your number by 2 and get a smaller one.
lets say your number is a. divide it by a positive number b. a(1/b) keep doing it a(1/b)(1/b) a(1/b)^n will never hit 0 but will keep becoming smaller with every increase in the number of times you divide it.
This the same argument as proving there is no largest positive real number.
By archimedes principle: given a<b there is some n in natural s.t. na>b, and given a>0 there is some n in natural s.t. 0 < 1/n < a
explain it little bit more plz....
when proving something you need to show theroems/lemmas/remarks about what you claim....
do you know what a natural number is?
ya
1, 2, 3, 4, ...
so you give me any number like: .00000000000000000000001 there is some 1/n that is smaller like 1/10000000000000000000000000000000
you could talk about density also, given and real number a<b there is some real number c such that a < c < b let a = 0
What if a=0.999... and b=1 ?
add a 9
between any two numbers there is an infinite amount of numbers
O.9999...
you actually did not show that you added another 9. it would be at the end of your ...
:)
There is no end to an endless string of 9s.
exactly
thus there is always a smaller number
or a number inbetween I should say
So there is a number in-between 1 and 0.999...?
.9999........ with endless 9's is not a finite number, just like infinity is not a finite number.
so you are asking a question that does not make since
1/3 =0.333... is a finite number!
1/3 is and the aproximation .33333333333 is an aproximation of 1/3 and yes its finite, but .333333333...... is not a real number if there are infinite 3's
we would say it approaches 1/3
2/3=0.6666...
1/3+2/3=1 the last time I checked
same thing, if you cant write the number its not finite, and you cant write .666666........(notice you have to do ......)
yes, but .333333333+ .6666666666 = .9999999999 != 1
you can write .333 untill the universe implodes, it will never be 1/3
lol, you are not getting my point. Can you write .333333......?
0.999...=1
No it doesn't.
it approaches 1, and is not finite untill you stop writing the 9
There is no "smallest" number in-between 0.999... and 1.
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