0.778g of one of the halogen was found to occupy a volume of 122 mL at a pressure of 99.8 kPa and a Temperature of 26 C. Which halogen was it?

Question

anonymous · Answer

I did: $$M= \frac{ mRT }{ pV }$$ 
m as 0.778, R as 8.13, T as 299, p as 99.8 and V as 0.122
What am I doing wrong.

anonymous · Answer

I found Fluorine. if it is right, I can answer.

anonymous · Answer

how did you do it?

anonymous · Answer

is it right ??

anonymous · Answer

don't know

anonymous · Answer

then it's better if i don't answer.

anonymous · Answer

it's more right then what i'm getting

anonymous · Answer

what did u do different?

anonymous · Answer

i used the formula for pM=drt and d=m/v

anonymous · Answer

may be you didn't use the correct units. you need SI units.

anonymous · Answer

which unit is not SI?

anonymous · Answer

i converted kPa into mmHg. basicly i was playing with the units. i was trying to reach a mass for a halogen. if it didn't work i'd use atm may be.

anonymous · Answer

:S I though kPa is what you use for pV=nRT

anonymous · Answer

kPa must be kilopascal. another pressure unit.