Question

Having issues with this one:
Divide:
2x^2-8x/4x-9 / x-4/4x-9

Answer 1

I have the first part done but then got lost.

Answer 2

You can cancel out the 4x-9s so you get 2x^2-8x/x-4

Answer 3

Uhoh where did the /x-4 come from?

Answer 4

isn't that what you wrote 2x^2-8x/4x-9 / **x-4**/4x-9

Answer 5

Yes

Answer 6

\[\frac{2x ^{2}-8x }{ 4x-9 }\div \frac{ x-4 }{ 4x-9 }=\frac{ 2x ^{2}-8x }{ 4x-9 }\times \frac{ 4x-9 }{ x-4 }\]

Answer 7

the 4x-9's go away

Answer 8

I understand that part

Answer 9

cancel each other out

Answer 10

Then you just divide or do you not know the dividing part?

Answer 11

2x^2-8x/x-4

Answer 12

do you know how to divide that?

Answer 13

2x^2/x-4 -8x/x-4 x-4 cancel out I dont know

Answer 14

you use long division. I will show you just a sec

Answer 15

k

Answer 16

It's basically the same as regular division.