Calculus Substitution Integrals (pic) http://dl.dropbox.com/u/16729527/calc26.jpg let u = ?, du = ?
put u =x^2
sorrry du=2x dx
doubt?
can you break it down solving it please :D
let u=4-5x^2
\[(1/2)\int\limits_{}^{} dt/(4-5t)\] this will be the integral after substitution
sorry replace t by u in it as we have u=x^2
would that end up being inverse sin(u)? or leave it alone
no.....not at all
its a linear form
see firstly relax and see all the formulas of integration
see all the forms of integration and then solve questions
ugh still not finding anything unless im suppose to solve sqroot(-1u) then id guess -1/sqroot(u) that doesnt seem right though
\(\large \int \frac{x}{\sqrt{4-5x^2}}dx \) Let \(\large u=4-5x^2 \) So \(\large du=-10xdx\rightarrow \frac{-1}{10}du=xdx \) So \(\large \int \frac{x}{\sqrt{4-5x^2}}dx = \frac{-1}{10}\int \frac{1}{\sqrt{u}} du\) rewrite that last integral so u can use the power rule...
hmm hahah that makes alot more sense LOL thanks a bunch man these sub integrals confusin me hard but im learning
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