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Mathematics 7 Online
OpenStudy (anonymous):

Calculus Substitution Integrals (pic) http://dl.dropbox.com/u/16729527/calc26.jpg let u = ?, du = ?

OpenStudy (anonymous):

put u =x^2

OpenStudy (anonymous):

sorrry du=2x dx

OpenStudy (anonymous):

doubt?

OpenStudy (anonymous):

can you break it down solving it please :D

OpenStudy (anonymous):

let u=4-5x^2

OpenStudy (anonymous):

\[(1/2)\int\limits_{}^{} dt/(4-5t)\] this will be the integral after substitution

OpenStudy (anonymous):

sorry replace t by u in it as we have u=x^2

OpenStudy (anonymous):

would that end up being inverse sin(u)? or leave it alone

OpenStudy (anonymous):

no.....not at all

OpenStudy (anonymous):

its a linear form

OpenStudy (anonymous):

see firstly relax and see all the formulas of integration

OpenStudy (anonymous):

see all the forms of integration and then solve questions

OpenStudy (anonymous):

ugh still not finding anything unless im suppose to solve sqroot(-1u) then id guess -1/sqroot(u) that doesnt seem right though

OpenStudy (anonymous):

\(\large \int \frac{x}{\sqrt{4-5x^2}}dx \) Let \(\large u=4-5x^2 \) So \(\large du=-10xdx\rightarrow \frac{-1}{10}du=xdx \) So \(\large \int \frac{x}{\sqrt{4-5x^2}}dx = \frac{-1}{10}\int \frac{1}{\sqrt{u}} du\) rewrite that last integral so u can use the power rule...

OpenStudy (anonymous):

hmm hahah that makes alot more sense LOL thanks a bunch man these sub integrals confusin me hard but im learning

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