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Mathematics 18 Online
OpenStudy (anonymous):

Differentiate: y=(sec^2)x + (tan^2)x

OpenStudy (anonymous):

Can't we solve it before proceeding further???

OpenStudy (anonymous):

what does that mean

OpenStudy (anonymous):

\[\sec^2(x) = 1 + \tan^2(x)\]

OpenStudy (anonymous):

This will give us : \[y= 1 + 2\tan^2(x)\]

OpenStudy (anonymous):

easier now we can use chain rule

OpenStudy (anonymous):

Yep, you can..

OpenStudy (anonymous):

Oh, I see. Thank you!

OpenStudy (anonymous):

You are welcome dear..

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