Question

I need help real quick with this radical question?

Answer 1

\[\frac{ 2 }{ 6-√3 } \]

Answer 2

rationalize the denominator?

Answer 3

How? Do you just multiply the top and bottom by √3?

Answer 4

\[\frac{2}{6-\sqrt{3}}*\frac{(6+\sqrt{3})}{(6+\sqrt{3})}=\frac{12+2\sqrt{3}}{36-3}=\frac{12+2\sqrt{3}}{33}\]

Answer 5

No...you are suppose to multiply the numerator and denominator by the reciprocal of 6-\[\sqrt{3}\} Which would be 6+

Answer 6

\[\sqrt{3}\]

Answer 7

Ohhhh. Okay that makes a lot more sense. With online school I can't really ask for help to understand things. Hard to just read a text and go off of it. Thanks so much, guys!