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Mathematics 8 Online
OpenStudy (anonymous):

What are the possible number of positive, negative, and complex zeros of f(x) = 2x^3 – 5x^2 – 6x + 4 ?

OpenStudy (anonymous):

You can try factoring and then solving the factors.

OpenStudy (anonymous):

I know that there are 2 or 0 positive zeros, and 1 negative zero. I have no idea how to get the complex zeros, I really would like to know how rather than just the answer of how there are 0 or 2 complex zeros.

OpenStudy (anonymous):

complex solutions always come in pairs

OpenStudy (anonymous):

so max number of complex roots is 2 but it's not garaunteed that there will be complex roots

OpenStudy (anonymous):

I tried to do factoring, and I got: x^2(2x - 5) - 2(3x - 2) So, would that make: (x^2-2)(2x-5)(3x-2)?

OpenStudy (anonymous):

Okay, thank you Mr. Me!

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