What are the possible number of positive, negative, and complex zeros of f(x) = 2x^3 – 5x^2 – 6x + 4 ?

Question

anonymous · Answer

You can try factoring and then solving the factors.

anonymous · Answer

I know that there are 2 or 0 positive zeros, and 1 negative zero. I have no idea how to get the complex zeros, I really would like to know how rather than just the answer of how there are 0 or 2 complex zeros.

anonymous · Answer

complex solutions always come in pairs

anonymous · Answer

so max number of complex roots is 2 but it's not garaunteed that there will be complex roots

anonymous · Answer

I tried to do factoring, and I got: 
x^2(2x - 5) - 2(3x - 2)
So, would that make: (x^2-2)(2x-5)(3x-2)?

anonymous · Answer

Okay, thank you Mr. Me!