Question

how do i find the equation of the line that intersects the graph of the parabola y=x"2 at x=-2 and x=1?

Answer 1

by finding the points with the values (-2,(-2)^2) and (1,1^2) and pushing the points thru a line equation setup when you find the slope between them

Answer 2

can you explain that a little simpler?

Answer 3

not really

Answer 4

if you were given 2 points in general, how would you find the equation of the line between them?

Answer 5

point slopr form

Answer 6

that would be fine, do you know how to find a slope between 2 points?

Answer 7

slope=y2-y1/x2-x1

Answer 8

youre doing great

so your real question is what are the points that it is asking for you to use

Answer 9

well i guess y1 is 4 and x is -2 and then 1 amd 1 ?

Answer 10

we know that a point is defined as:

(x,y)

and it is given the y=x^2 which allows us to write the point as:

(x,x^2)

point1 is when x=-2
point2 is when x =1

Answer 11

yep, you got them

Answer 12

(-2,4) and (1,1) are the points they are wanting you to use

Answer 13

then i use y-y1=m(x-x1) ?

Answer 14

yep, and the (1,1) looks like an easy point to use in that; what is the slope?

Answer 15

-1
?

Answer 16

correct, m=-1 sooo

y-1 = -(x-1) and they might want it in a y= format

y = -x+2 seems about right

Answer 17

thanks

Answer 18

youre welcome :)