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Mathematics 13 Online
OpenStudy (anonymous):

question inside :)

OpenStudy (anonymous):

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OpenStudy (anonymous):

this is the question, in case my handwriting/drawing is hard to see :P

OpenStudy (anonymous):

answer choices A,B,C,D from top to bottom :)

OpenStudy (anonymous):

5x

OpenStudy (anonymous):

how'd u get that? :O

OpenStudy (anonymous):

im not quite sure if i am understanding this right, but did u just make the 5x not an exponent, so that takes out the ln, so you get e=5x ?? idk is that right?

jimthompson5910 (jim_thompson5910):

ln is a natural log which 'undoes' the exponential function with 'e' as a base so basically ln(e^x) = x and e^[ ln(x) ] = x which tells you that f(x) = ln(x) and g(x) = e^x are inverse functions

OpenStudy (anonymous):

okay, wait so my answer is ln(x) ? or is it ln(5x) ?

jimthompson5910 (jim_thompson5910):

no i'm just saying in general

OpenStudy (anonymous):

wait scratch that... there is no ln(5x) haha my bad... or is it just 5x ?

OpenStudy (anonymous):

ohhh okay :P i see

jimthompson5910 (jim_thompson5910):

in my example, replace each 'x' with '5x'

OpenStudy (anonymous):

okay :) so my answer is B. 5x because of that? since e=x ? and x = 5x ?

OpenStudy (anonymous):

is that right? since u said e=x right?

jimthompson5910 (jim_thompson5910):

you are correct, and no i didn't say e = x

jimthompson5910 (jim_thompson5910):

not sure where you got that

OpenStudy (anonymous):

oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

jimthompson5910 (jim_thompson5910):

i gotcha

OpenStudy (anonymous):

oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

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