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Algebra 9 Online
OpenStudy (anonymous):

Help needed??

OpenStudy (anonymous):

Find the total area of all shaded rectangles. This is about Polynomials have no idea where to start

OpenStudy (anonymous):

Step by step if possible

OpenStudy (allank):

What you want to do first is identify the rectangles. I spot two. Do you?

OpenStudy (anonymous):

I am so confused right now

OpenStudy (anonymous):

I am confused and i do not even get my question i post

OpenStudy (anonymous):

I completely understand

OpenStudy (anonymous):

looks like they are all shaded

OpenStudy (anonymous):

since they are all shaded, and since you have a square, the area is the square of the side the length of the side is \(3x+4\) so the total area is \((3x+4)^2\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

How did you get that?

OpenStudy (anonymous):

by looking across the top and adding the two lengths. one is \(3x\) the other is \(4\) so the total length is \(3x+4\)

OpenStudy (anonymous):

and therefore the total area is \((3x+4)^2\)

OpenStudy (anonymous):

See the book is horrible at explaining how to do this, what does this have to do with Polynomials

OpenStudy (anonymous):

the other answer is the area of the large square, which is \(3x\times 3x=9x^2\) plus the area of the small square which is \(4\times 4=16\) plus the area of the two reactangles, each of which is \(3x\times 4=12x\) when you add these you get \[9x^2+12x+12x+16=9x^2+24x+16\]

OpenStudy (anonymous):

they are trying to get you to see by making a square, that \[(3x+4)^2=9x^2+24x+16\]

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