Question

Write an equation for the quadratic function whose graph contains the given vertex and point
Vertex: (1,3), Point: (-4,-27)
Please explain how you come to the answer!

Answer 1

y=a(x=1)^2+3

Answer 2

a(x+1)^2+3

Answer 3

then put in the other points

Answer 4

-27=a(-4+1)^2+3

Answer 5

sooo
y=2(x-1)^2+3

Answer 6

u'll get the slope

Answer 7

yea thats using the vertex

Answer 8

then u substitue the other points of the graph

Answer 9

to get the slope

Answer 10

okay

Answer 11

n ones u get the slope u use the slope and the vertex only to get the equation

Answer 12

what?

Answer 13

\[-27=a(-4+1)^2+3 -27=9a=3 -30=9a a=3\]

Answer 14

then use the info u have
y=3.3(x-1)^2+3

Answer 15

thats the equation]

Answer 16

how does that go to a y=ax^2+bx+c form? i want to know how you fit the things into this form.

Answer 17

i think

Answer 18

just open the brakets up

Answer 19

okay?

Answer 20

n the exponets

Answer 21

i got the ans y=3.3x^2-6.6x+6.3

Answer 22

k bye