Question

solve for x in the given interval sqrt2sinx+tanx=0 (-pi,pi)

Answer 1

even i'm waiting for someone to answer your question... eager to know ...

Answer 2

sabika only sin x is underroot or whole?

Answer 3

sqrt2sinx ***

Answer 4

sqrsinx + tanx = 0
sqrsinx = - tanx
sinx = tan^2x squaring both sides
1 = 1/cosx dividing both sides by sinx
cosx = 1 crossmultiplying
x = 0

i am not sure ... .. but i just tried i am also learning trigonometry

Answer 5

@sabika13 check my answer... i think i am so right.... tell me

Answer 6

sorry it was sqrt 2 sinx

Answer 7

1st time in my life i had tried such trig equ omg omg.... :( :(

Answer 8

sqrt 2sinx + tanx = 0
sqrt 2sinx = -tanx
squaring both sides we get
2sinx = tan^2x
2 = sinx/cos^2x

Answer 9

sabika, before ppl can help you, they need to understand your question clearly. even now your question is vague... not clear.....
is it sqrt2(sin x ) or sqrt(2sin x ) ?

Answer 10

@rizwan_uet can you keep going or are you stuck?
@jatinbansalhot its sqrt2sinx

Answer 11

2cos*2x=sinx
2(1-sin^2x) = sinx
2-2sin^x -sinx = 0
sinx(-2sinx -1) = -2

Answer 12

i m trying......

Answer 13

-2sin^2x-sinx +2 = 0 is good! thanks!!

Answer 14

its right or not???

Answer 15

hhahahahaahahahahahahha... i'm not going to solve her problem... she is not clear...

Answer 16

? i dont know if its right.. thats why im asking a question..

Answer 17

up to this point i did my best but the rest is difficuilt for me sorry..

Answer 18

x = pi / 4, -pi / 4 .... m i right

Answer 19

sqrt 2sinx + tanx = 0
sqrt 2sinx = -tanx
after squaring both sides we get
2sinx = tan^2x
or sinx(2-sinx/(cos^2x))=0
then sinx=0 or x=0,pi,-pi (one part )
the other part may can be obtained from (2-sinx/(cos^2x))=0

Answer 20

how did you go from 2sinx=tan^2x to sinx(2-sinx/cos^2x0 =0 ?

Answer 21

use tanx=sinx/cosx

Answer 22

yeah so sin^2x/cos^2x =2sinx
2sinxcos^2x=sinx^2
2sinx(1-sin^2x)=sin^2x
... am i doing it right?

Answer 23

2sinx cos^2x = sin^2x i have taken this statement from you
2sinx ( 1 - sin^2 ) = sin^2x
2sinx - 2sin^3 =sin^2x
2sinx - 2sin^3 - sin^2x = 0
2sin^3 + sin^2x - 2sinx = 0
sinx( 2sin^2 + sinx - 2 ) = 0

Answer 24

@sabika13 did my work help u? i want to know ..... do tell me