Question

solve for x in the given interval
2tanx=secx (-2pi,0)

Answer 1

\(\large 2tanx=secx \)
\(\large 2\frac{sinx}{cosx}=\frac{1}{cosx} \)
\(\large \frac{2sinx}{cosx}=\frac{1}{cosx} \)
\(\large 2sinx=1 \) numerators must be equal
\(\large sinx=\frac{1}{2} \)

Can you do the rest from here?

Answer 2

Yess thank you :D