Find the domain of f(x)= 2/(x-3)-5
all real nos. except 3
all real number except 3 and 8
How do I know for sure though? Like why is the answer "all real numbers except 3 and 8"?
denominator can be equal to 0. only for those x values for which denominator is zero will not be included in the domain..
@iceywheniplease7 thanks for medal...
You're welcome thank you for explaining it to me and helping me out!
all are welcome.... see you @iceywheniplease7 .....
the way of this problem was written...number 5 is a separate constant, it's not in the denominator, so number 8 is wrong...it's only number 3 that x cannot be
if 5 is also part of denominator then 8 will be included otherwise it will not...... from the given problem it looks like 5 is part of denominator....
5 is not apart of it.
no @jatinbansalhot, if 5 is in the denominator ..then you can rewrite that expression as : f(x) = 2/(x-8) ...and hence ...8 is the only answer..so either way, answer of both 3 and 8 is wrong..
icey, look at matricked answer..only 3 is not in the domain
@tamtoan we can simplify the expression but we can't change the original domain... do you know about limit... then you can understand me..
@tamtoan .... maybe i'm not the correct.... confirm and tell @iceywheniplease7
@jatinbansalhot , this is just a simple algebra funtion, and by the way, i do know limit :)...try to read the problem again..and icey already said 5 is not a part of it :)
Yes. So thank you for bringing this to our attnetion Tamtoan :)
np, icey and jatinbansalhot :), we are all human..we do make mistakes sometimes, hope you get it straight, and jatinbansalhot explanation of denominator cannot be zero is excellent. , have a good time to both
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