Question

please help

6tanθ−6cotθ=0

Answer 1

divide both sides by 6 so your equation is now: tanx - cotx = 0
let's use "x" instead of "theta"... easier to type...

Answer 2

ok....tanx-cotx=0 then wat?

Answer 3

try writing the equation in terms of only sin and cos....

Answer 4

ok is 45 135 225 n 315 the solutions?

Answer 5

idk... i didn't solve.... yet....
maybe these guys will...

Answer 6

\[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]

Answer 7

\[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle

Answer 8

yes

Answer 9

One answer will be in quadrant 1 the other in 3.

Answer 10

ok i just got it thank u all!

Answer 11

hold on. i think you were right above

Answer 12

if each term is squared then there wil be no negative numbers

Answer 13

and you will have 4 solutions

Answer 14

45, 135, 225, 315

Answer 15

yup

Answer 16

Good job

Answer 17

thank u tho

Answer 18

when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ...

** i don't know to to write in the form like chme does, or else, it would look much easier.

Answer 19

its the equation button below the this text field.

Answer 20

i got it, thanks @chme very much