Question

i need help..
pls. undo this to have formula of integration
Dx K = 0
Dx (X^n) nx^n-1

Answer 1

like rewrite it. so k = 0 dx and x^n = nx^(n-1) dx ??

Answer 2

for example like this:
Dx(x)=1 so the integration formula is (sign of integral dx=x)

Answer 3

pls. help me..

Answer 4

i think i see what you're doing...
Dx [x] = 1 means "derivative of x = 1"

so do you want the integral counterpart of this??? like:
\(\large \int 1 dx = x + C \) ????

Answer 5

can you explain what it is that u want?

Answer 6

yah, thats what i mean..

Answer 7

ok.. so the power rule counter-part to derivatives: \(\large D_x[x^n]=n\cdot x^{n-1} \)

would be the power rule for integration: \(\large \int x^ndx=\frac{1}{n+1} \cdot x^{n+1}+C \)

Answer 8

Dx (x) = 1
∫dx=x

Answer 9

^^^ yes.. but don't forget the constant of integration "+ C"

Answer 10

ahmm.. :)
how about the first one ..
Dx k =0??

thanks for your help..

Answer 11

the integration counterpart for constants "K": \(\large \int Kdx=K\cdot x + C \)

Answer 12

i know what you're thinking: \(\large \int 0dx = \) ????

Answer 13

is it right my own answer in question number 2?
dx^n/dx nx^n-1

the integration is like that
∫x^ndx=x^n+1 / n+1 + C ??

Answer 14

yes... that's correct....

Answer 15

so it means either of our two answer are both correct?

Answer 16

im really sorry for my sentence construction .. :)
i hate english sorry i am not good in english..

Answer 17

they're the same: \(\large \frac{x^{n+1}}{n+1}=\frac{1}{n+1}\cdot x^{n+1} \)

Answer 18

my ingrish isn't that great either...

Answer 19

thank you so much..

Answer 20

yw... :)

Answer 21

takecare! :)
i owe you a lot..

Answer 22

no problem...
you don't owe me anything... :)

Answer 23

bye.... :)

Answer 24

:)