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Mathematics 16 Online
OpenStudy (anonymous):

Divide. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/Equation.jpg A. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/A-2.jpg B. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/B-2.jpg C. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/C-2.jpg D. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/D-2.jpg A, B, C, or D? Please explain (:

OpenStudy (anonymous):

\[\frac{\frac{x^2 + 2x + 1}{x - 2}}{\frac{x^2 - 1}{x^2 - 4}}\] note that both x^2 - 1 and x^2 - 4 are the difference of two squares, which means they can be written as (a + b)(a - b) Also not that x^2 + 2x + 1 can be written as (x + 1)^2 So the problem becomes: \[\frac{\frac{(x + 1)^2}{x - 2}}{\frac{(x - 1)(x + 1)}{(x - 2)(x + 2)}}\] \[\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}\] Using that we get \[\frac{(x + 1)^2(x - 2)(x + 2)}{(x - 2)(x - 1)(x + 1)}\] cross out the factors that are the same: \[\frac{(x + 1)(x + 2)}{(x - 1)}\] It can't be simplified any futher, so the answer is A :)

OpenStudy (anonymous):

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