Please help!! I am almost done with my entire Algebra!!
9.03] Part 1 − Find the vertex, axis of symmetry, domain, and range of the graph of y = −2x2 − 6x + 1. Show all work for full credit.

Part 2 − Using complete sentences, explain how you can determine the axis of symmetry, the domain, and range without graphing y = −2x2 − 6x + 1.

Question

Please help!! I am almost done with my entire Algebra!!
9.03] Part 1 − Find the vertex, axis of symmetry, domain, and range of the graph of y = −2x2 − 6x + 1. Show all work for full credit.

Part 2 − Using complete sentences, explain how you can determine the axis of symmetry, the domain, and range without graphing y = −2x2 − 6x + 1.

anonymous · Answer

To start with, we get the vertex form of the equation.

y = -2(x^2 + 3x) + 1     ->      y = -2(x^2 + 3x + 9/4) + 1 + 2(9/4)

y = -2(x + 3/2)^2 + 11/2

anonymous · Answer

So, this is a parabola opening downward with a maximum at (-3/2, 11/2) which is also the vertex.  From this vertex, we also know that the axis of symmetry is at x = -3/2.

So, we can put any value we want for x, so the domain is all real numbers.  And since the max is at 11/2, the range is y <= 11/2

anonymous · Answer

Is that it?

anonymous · Answer

Are there any other questions you have with this problem?

anonymous · Answer

Thx for ur help!! :D|dw:1353515335486:dw|
Nope, I got it! Thx! :D

anonymous · Answer

That's right! you're the smiley-girl!

anonymous · Answer

Ha! Thx for the nickname! LOl, :)

anonymous · Answer

uw!  Have good turkey!

anonymous · Answer

You too! :)

anonymous · Answer

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