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Physics 6 Online
OpenStudy (anonymous):

Prove that the resulting force from the two springs is equal to F = -2kx ( 1 - L/(sqrt(L^2 +x^2)) . What I did was to separate each component for each force. Fx = - kx cos theta - kx cos theta = -2kx cos theta. Fy = kx sin thetha - kx sin theta = 0 I try to switch cos theta but I won't reach the answer. \[F = -2kx ( \frac{ x^2 }{ \sqrt(L^2 + x^2) })\] http://img805.imageshack.us/img805/8127/asfdasf.png

OpenStudy (anonymous):

c if this helps

OpenStudy (anonymous):

What did you do in the part where you crossed it

OpenStudy (anonymous):

just taken the components

OpenStudy (anonymous):

ahh

OpenStudy (anonymous):

did you get it

OpenStudy (anonymous):

Yeaa, the minimium I can compress it, it's L

OpenStudy (anonymous):

k then bye.

OpenStudy (anonymous):

Thanks, alot! :D

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