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For the function g(x) =32/x+3 , find (g-1 º g)(5).
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If you have: \[f(x); f^{-1}(x)\] Then: \[f^{-1}(f(x))=x; \forall x\] So: \[g^{-1}(g(5))=5\]
okay so what is the answer... the choices are 11,5,2,1
The last line...
did you see the choices?
11 5 2 or 1
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Did you see the last line in my response?
FOR ANY X VALUE: \[g^{-1}(g(x))=g(g^{-1}(x))=x\] You want x=5. You're done.
okay thank you
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