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What's the second derivative of f(x)= sec^2 (pix)?
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cos^2
^incorrect.
i thnk so
The answer would be: \[\frac{d}{dx} \left( \frac{d}{dx}(\sec^2(\pi x)\right)=\frac{d}{dx} \left( 2 \pi(\sec^2( \pi x)\tan(\pi x) \right)\] From the product rule. If you look CAREFULLY you see that if we differentiate whats left we do the product rule, one of them involves the derivative of sec^2(pi x) which we JUST FOUND, so use that result to get: \[4 \pi^2 \sec^2(\pi x)\tan^2(\pi x)+2 \pi^2 \sec^4(\pi x)\]
Not cos^2
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check derivative section http://www.wolframalpha.com/input/?i=2+%CF%80+sec%5E2%28%CF%80+x%29+tan%28%CF%80+x%29&lk=1&a=ClashPrefs_*Math-
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