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Mathematics 16 Online
OpenStudy (anonymous):

limit

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0^+} \frac{1+\cos x}{e^x-1}\]

hartnn (hartnn):

directly put x=0

OpenStudy (anonymous):

2/0

hartnn (hartnn):

2/0 = ?

OpenStudy (anonymous):

infty

hartnn (hartnn):

yes.

OpenStudy (anonymous):

if it asks to use lhosp. rule

hartnn (hartnn):

cnoot be used, the form is neither 0/0, nor infty/infty

hartnn (hartnn):

*cannot

OpenStudy (anonymous):

I trid rationalizing with 1-cosx \[\frac{ \sin^2x }{ (e^x-1)(1-\cos x) }\] 0/0

hartnn (hartnn):

cos 0 =1 so u just multiplied by 0/0 not allowed.

OpenStudy (anonymous):

great thanks

hartnn (hartnn):

welcome ^_^

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