Question

3 √52 +2√208 – 2 √117

Answer 1

you would simplify radical 52 to radical 4 and radical 13 right?

Answer 2

Factor 52, 208, and 117 to see which perfect squares can be facored out.
52 = 4 x 13, so\[3 \sqrt{52} = 3 \sqrt{4 \times 13} = 3 \sqrt{4} \sqrt{13} = 6 \sqrt{13}\]
Try the same with 208 and 117

Answer 3

Yes, you are correct, radical 52 is radical 4 times radical 13. Dothe same simplification to radical 208 and radical 117

Answer 4

I need help with that part

Answer 5

Since you know that radical 52 includes 13 in it, try dividing both 208 and 117 by 13. You see that radical 208 = radical 16 times radical 13, and radical 117 is radical 9 times radical 13

Answer 6

so 6 radical 13 +4 radical 13 -3 radical 13

Answer 7

\[3 \sqrt{52} + 2 \sqrt{208} - 2 \sqrt{117}\]
\[3 \sqrt{4} \sqrt{13} + 2 \sqrt{16} \sqrt{13} -2 \sqrt{9} \sqrt{13}\]

Answer 8

\[6\sqrt{13} +4\sqrt{13} -3\sqrt{13}\]

Answer 9

Remember that radical 208 and radical 117 have numbers multiplying them

Answer 10

sorry saw my mistake

Answer 11

Great, you're getting there

Answer 12

Ya im done with this prob. YAy