Write and equation for each vertical and horizontal asymptotes to the graph.

Question

anonymous · Answer

$$\frac{ 2x-2 }{ x^2+x-2 }$$

anonymous · Answer

ik the asymptotes are at y=-2 and x=0 but im not sure what the question is asking

anonymous · Answer

write an equation*

anonymous · Answer

How did you get y=-2 and x=0?

anonymous · Answer

if you graph it, the vertical is -2 and 0 is the horizontal

anonymous · Answer

Horizontal is y=0

anonymous · Answer

thats what i said...

anonymous · Answer

You said x=0.

but thats what it means by whats the equation. just y=0 for horizontal

anonymous · Answer

ok then how would i justify that????

anonymous · Answer

What do you mean?

anonymous · Answer

it says Write an equation for each vertical and horizontal asymptote to the graph. Justify!

anonymous · Answer

Well since the exponent on x is larger in the numerator than it is in the denominator that always means theres a horizontal asymptote of y=0

anonymous · Answer

its larger in the denominator.. not the numerator?

anonymous · Answer

Yep, my mistake, reverse it

anonymous · Answer

o ok i was confused for a second haha

skullpatrol · Answer

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zzr0ck3r · Answer

the horizontal asymptote will be the domain restriction on the inverse

anonymous · Answer

(x+2)(x-1)

anonymous · Answer

wait what.....?

skullpatrol · Answer

So x can not equal -2 and 1 right?

zzr0ck3r · Answer

if it is a horizontal asymptote the equation will be y = something
if its verticle the equation will be x = something

anonymous · Answer

but those are discontinuities not asymptotes

anonymous · Answer

but i need to JUSTIFY why

skullpatrol · Answer

skullpatrol · Answer

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