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Mathematics 18 Online
OpenStudy (anonymous):

One more question that i could not understand

OpenStudy (anonymous):

\[\int\limits_{}^{} \coth(\frac{ \theta }{ \sqrt{3} }) d \theta \]

hartnn (hartnn):

write coth = cosh / sinh

hartnn (hartnn):

then use \(\\ \huge \text{In general,}\int \frac{f’(x)}{f(x)}\:dx=\ln|f(x)|+c \)

hartnn (hartnn):

where f(x) = sinh

hartnn (hartnn):

making a substitution before will simplify things x= theta / root 3 dx=... ?

OpenStudy (anonymous):

dx= 1/root3 d(theta)

hartnn (hartnn):

yeah, so dtheta = root 3 dx rewrite the integral with this substitution

OpenStudy (anonymous):

\[\int\limits_{}^{} \frac{ \cosh }{ \sinh } x \sqrt{3}dx\]

hartnn (hartnn):

\(\large \int\limits_{}^{} \frac{ \cosh x}{ \sinh x} \sqrt{3}dx\)

hartnn (hartnn):

here f(x) = sinh x and use that general formula i gave. what u get ?

OpenStudy (anonymous):

\[\sqrt{3}\ln \sinh +c\]

hartnn (hartnn):

thats correct. did u get all steps ?

hartnn (hartnn):

and u missed a 'x'

hartnn (hartnn):

don't forget to resubstitute x= theta / root 3

OpenStudy (anonymous):

ok i get it now.. Thank for your guiden

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

but how come the last answer become this...\[\sqrt{3}\ln[ \frac{ e^\frac{ \theta }{ \sqrt{3} }-e^\frac{ - \theta }{ \sqrt{3} } }{ 2 }]\]

hartnn (hartnn):

by using the defination of sin h theta.

OpenStudy (anonymous):

ok.. using the hyperbolic fuctions >>

hartnn (hartnn):

yes, u know the difinition, right ?

OpenStudy (anonymous):

yes.. i know.. but i still not remember it..

hartnn (hartnn):

\(\huge \sinh x= \frac{e^x-e^{-x}}{2}\)

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