One more question that i could not understand
\[\int\limits_{}^{} \coth(\frac{ \theta }{ \sqrt{3} }) d \theta \]
write coth = cosh / sinh
then use \(\\ \huge \text{In general,}\int \frac{f’(x)}{f(x)}\:dx=\ln|f(x)|+c \)
where f(x) = sinh
making a substitution before will simplify things x= theta / root 3 dx=... ?
dx= 1/root3 d(theta)
yeah, so dtheta = root 3 dx rewrite the integral with this substitution
\[\int\limits_{}^{} \frac{ \cosh }{ \sinh } x \sqrt{3}dx\]
\(\large \int\limits_{}^{} \frac{ \cosh x}{ \sinh x} \sqrt{3}dx\)
here f(x) = sinh x and use that general formula i gave. what u get ?
\[\sqrt{3}\ln \sinh +c\]
thats correct. did u get all steps ?
and u missed a 'x'
don't forget to resubstitute x= theta / root 3
ok i get it now.. Thank for your guiden
welcome ^_^
but how come the last answer become this...\[\sqrt{3}\ln[ \frac{ e^\frac{ \theta }{ \sqrt{3} }-e^\frac{ - \theta }{ \sqrt{3} } }{ 2 }]\]
by using the defination of sin h theta.
ok.. using the hyperbolic fuctions >>
yes, u know the difinition, right ?
yes.. i know.. but i still not remember it..
\(\huge \sinh x= \frac{e^x-e^{-x}}{2}\)
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