Graph the function f(x) = x + 4 / x Graph the secant line that passes through the points (1,5) and (8,8.5) on the same set of axes Find the number c that satisfies the conclusion of the Mean Value Theorem for f on [1,8]
for the mean value theorm says that assuming that f(x) is continious over the range [1 8], and is differential over the same interval the the derivitave at c will have the same slope as the line made by the 2 given lines. f'(x) = (f(b)-f(c))/(b-a)
so first take the deritive of f(x)
did you solve it yet ?
the derivative gives us an equation, a function, that we can use to define the slope at any point along the curve. so, we need to know what the slope is between the points given to compare with
Wait, so do I have the sketch the whole graph ( therefore find the asymptote, critical point,etc...?)
y=f(x) y' = f'(x) defines the slope at every value of x given 2 points; (a,f(a)) and (b,f(b)) we determine the slope between them as\[\frac{f(b)-f(a)}{b-a}\] there exists some point c in the interval from a to b such that the derivate defined at c is equal to to the slope of the secant between a and b\[f'(c)=\frac{f(b)-f(a)}{b-a}\]
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what is the slope between (1,5) and (8,8.5) ??
So I would do this (2c)(c) - (c ^2) / c^2 = f(1) - (f8)/1-8 . Sorry my computer was derping I couldnt write the answer properly
yes, but let me chk your derivative (x + 4) / x 1+4x^(-1) -4x^(-2) is what i get
nono it goes like this x + (4/x) so i simplified to x^2 +4/x so I used the product rule to give me the final answer?
(x + 4) / x; x=8 ... 12/8 not equal 8.5 murmur so its 2 terms x + 4x^(-1) 1- 4x^(-2)
ok, so what the slope between the points given?
Hum you take the initial formula and I plugged in 1 and 8 to give me f(1) = 5 and f(8)= 3/2. THen I would need to use a quadratic formula to solve for c?
(8,8.5) -(1,5.0) -------- 7,3.5 ; slope = 35/70 = 1/2
Shouldn't i use the point 1, and 8 and find the x for those points? or I have to use 8.5?
1 and 8 are the xs for those points; and 5 and 8.5 are the ys that result .. they already did that part for you
1 - 4c^(-2) = 1/2 - 4c^(-2) = -1/2 4/c^2 = 1/2 8 = c^2
Ah thank you it makes much more sense! thanks a lot!
youre welcome, good luck
notice that 2sqrt(2) is in the interval from 1 to 8, thereby validating the mean thrm
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