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Mathematics 21 Online
OpenStudy (anonymous):

using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|

OpenStudy (mathstudent55):

Make a table of values for each function. To do that, come up with some values for x and calculate f(x) and g(x) f(x) = |x| x | f(x) ---------- -2 | 2 -1 | 1 0 | 0 1 | 1 2 | 2 Use the above points to graph f(x). Then do the same for G(X)

OpenStudy (anonymous):

@samnatha r u there?????/

OpenStudy (anonymous):

yes sorry was just tying to work it out

OpenStudy (anonymous):

i then have to solve |x| = | 2x-3|

OpenStudy (anonymous):

is anyone there ?

OpenStudy (mathstudent55):

No. You don't need to solve that equation. Just make two tables of points and graph both on the same x-y graph

OpenStudy (anonymous):

oh ok thanks theres another one which is |2x-3| < |x|

OpenStudy (mathstudent55):

Sorry, I misread your post. When you said you have to solve |x| = |2x - 3|. I thought you meant that you needed to solve that to get the graph. After you graph both f(x) and g(x on the same graph, see where the graphs intersect. That's the solution to|x| = |2x - 3|

OpenStudy (anonymous):

ok thanks i got that bit but i'm not too sure on the second bit

OpenStudy (mathstudent55):

|dw:1353697888667:dw|

OpenStudy (mathstudent55):

The soulition to |x| = |2x - 3| is where the two graphs intersect. There are two points.

OpenStudy (anonymous):

(1,1) and (3.5, 3.5) thats what i got on my graph is that right ?

OpenStudy (mathstudent55):

The solution to |2x - 3| < |x| is the x values for which the value of g(x) is less than the value of f(x). If you look in graph, see where the y vaslue of g(x) is lower than the y value of f(x).

OpenStudy (mathstudent55):

I think it's (1,1) and (3,3)

OpenStudy (anonymous):

ok my graph is probs a bit diff but thanks for your help :)

OpenStudy (mathstudent55):

You're welcome

OpenStudy (anonymous):

god the pressures of leaving cert math

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