Question

solve for z, and give your answer in the form a + bi

(conj)z+2z = 2+4i+conj(7+3i)

**conj refers to conjugate of a complex number
(a line on top of it)

Answer 1

answer is 3+i (need to learn how to do it)

Answer 2

I don't understand the notation of the equation. Why did you put (conj)? Does it mean take the conjugate of the term that follows it? Or multiply that term by its conjugate? Or what?

Answer 3

i dont know how to write a line above the letter for this

Answer 4

so for this question, there would be a line above the z and the 7+3i

Answer 5

z = a + bi
(conj)z = a - bi

Answer 6

it means to flip the sign of the imaginary part

Answer 7

So why don't you just write z - 2z = 2 + 4i + (7 - 3i)? Is that what the question says?

Answer 8

no, there is no line above the z+2z, just the z

Answer 9

Can you draw the question instead?

Answer 10

\(\bar{z} + 2z = 2 + 4i + \overline{7+3i} = 2 + 4i + 7 - 3i = 9 + i\)

Answer 11

answer is 3+i though...you seem to be on the right track though

Answer 12

no idea what the conjugate of a variable means...

Answer 13

unless you use fourier which i don't think you are

Answer 14

It's not my problem statement. You need to be on the right track.

Where shall we go from here? \(\bar{z} + 2z = 9 + i\)

Answer 15

i dont know what the z part is. that is the problem

Answer 16

is z considered real or imaginary?

Answer 17

i tried it with both for hours

Answer 18

Please read the problem statement.

"solve for z, and give your answer in the form a + bi"

z is a Complex Number

Answer 19

oh

Answer 20

You tried what?

\(\bar{z} + 2z = a - bi + 2(a + bi) = a - bi + 2a + 2bi = (a + 2a) + (2b-b)i\)

Do yuo see where this is going?

Answer 21

no

Answer 22

i understand why you get this but why did you do this

Answer 23

you equate this to 9+i?

Answer 24

That is it! \(3a + bi = 9 + i\)

Answer 25

thanks