Question

Why can't L'Hopitals Rule be used for this indeterminate?
limit as x approaches 0 for e^(2x)/x ?

Answer 1

Why is it indeterminate?

Answer 2

O sorry I didn't reaize you were going to answer so quickly. Because it would be 0/0?

Answer 3

Well, when x approaches 0, why will e^(2x) become 0?

Answer 4

O, I guess it wouldn't, it will become e^0 making it 1/0? I gave wrong equation it is , limit as x approaches 0 f(x)= (e^(2x) -1)/x

Answer 5

You can use L'Hopital then

Answer 6

the answer would then be 2

Answer 7

Right, and that is the limit