Question

Find a quadratic equation in standard form in standard form with integral coefficients and having the give numbers as its roots.

Answer 1

\[3-2\sqrt{7} , 3+2\sqrt{7}\]

Answer 2

x = 3 - 2sqrt7 and x = 3 + 2 sqrt 7\

x -(3-2sqrt7) and x -(3+ 2sqrt7)

Now multiply them both:

\[[x-(3-2\sqrt7)] \times [x - (3+2\sqrt7)]\]

Answer 3

You should get:
\[\Large x^2-6x-19\]

Answer 4

ahhh. Thank you.

Answer 5

You're welcome.