Question

What is the solution of the system? Use substitution.

x = –2y + 10
–6y = 6x – 6
z = –3x + 10y

Answer 1

A. (6, 12)

B. (–12, –6)

C. (–6, –12)

D. (2, 4)

Answer 2

Is it A?

Answer 3

Solve two at a time.

Answer 4

1. Label the three equations

x = –2y + 10 -(1)
–6y = 6x – 6 -(2)
z = –3x + 10y -(3)

2. Sub equation (1) into equation (2). Then solve it, you can get the value of y... Hmm... Are you posting the right question?

Answer 5

A. x = 9, y = –8, z = 114

B. x = –8, y = 9, z = 114

C. x = –8, y = 114, z = 9

D. x = 114, y = 9, z = –8

Answer 6

yeah, now options are correct....

Answer 7

I posted the wrong options- now, would it be A?

Answer 8

How do you get A?

Answer 9

9, -8

Answer 10

No, it won't be A ..

Answer 11

What did you get on solving the equations? x,y.z?

Answer 12

@sassyj Can you solve the first two equations or do you need help?

Answer 13

I cant do it

Answer 14

I dont get any of this-even reading the textbook

Answer 15

x = –2y + 10 -(1)
–6y = 6x – 6 -(2)
z = –3x + 10y -(3)

Sub equation (1) into equation (2), that means when you see x, replace x by –2y + 10. Do you get this part?

Answer 16

yes

Answer 17

So, try it. Sub. (1) into (2), what do you get?

Answer 18

If you really don't understand how substitution works, I suggest you to watch a short video on Khan Academy first
http://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/v/practice-using-substitution-for-systems