Question

1 Which is the right period, amplitude and phase shift of this trigonometric function y = 6 pie cos ( 3 pie x + 2 )

Answer 1

The general equation is
\(\large y = Asin(\omega x+\theta)\)
where
A is the amplitude,
Period = T = 2\(\pi\)/\(\omega\)
and phase shift = \(\theta\)

Answer 2

can u get those parameters now ?

Answer 3

yes, thank you so much. im stuck with these assignments,

Answer 4

welcome, if you don't get correct values, you can ask :)

Answer 5

heres another :) y = sin x
If we shift the function -2 units vertically and 3 units to the right, what would bethe translated function?

Answer 6

vertical shift of -2 means, 2 units down,
if y was 0 previously, now it will be -2
so, y is replaced by y+2,
similarly , x will be replaced by x+3
ok ?

Answer 7

got it, thank you so much, your an angel :)

Answer 8

i am just a helping human :) and welcome ^_^

Answer 9

hello, help again, i cant get he correct answer.
Find the derivative of the function:
a) log square( cos(2x) + x cube) and b) log x over 3x square

Answer 10

if u tried it, u show your work, i will try to find error.

Answer 11

i have no scanner here,my papers are all over my bed (:

Answer 12

ok, the question is \(\log^2[\cos2x+x^3]\)
right ?

Answer 13

yes