Hello! Could somebody tell me how can I linearizing a second order non-linear equation? So I have f(x,y)= xy. Can I make a linear approximation on the f(x,y) function? Thank you!
y = f(a) + f '(a) (x - a)
is this tangent to f ?
yes
thank you!
its actually, \(\large f\left(x,y\right)\approx f\left(a,b\right)+\frac{\partial f}{\partial x}\left(a,b\right)\left(x-a\right)+\frac{\partial f}{\partial y}\left(a,b\right)\left(y-b\right).\) for 2 variables.
y = f(a) + f '(a) (x - a) applies only for f(x) as the function of x only....
here u get \(\huge \frac{\partial f}{\partial x}=y \\\huge \frac{\partial f}{\partial y}=x \)
so, \(\huge \frac{\partial f(a,b)}{\partial x}=b \\\huge \frac{\partial f(a,b)}{\partial y}=a \\ f(a,b)=ab\) now just plug in values.
@silvia
@hartnn thank you!
welcome ^_^
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