Cesium-137 is a radioactive material that decays at the rate of 2.3% per year. Suppose a nuclear accident releases Cesium-137 into the atmosphere at a constant rate of 1.5 pounds per year for the next 30 years. What is the total amount of radioactive buildup?

Question

anonymous · Answer

I'm pretty sure this formula is part of it...
$$\frac{ p }{ k }(1-e ^{-kt})$$

I dont know what k (rate would be....0.23 or 1.5?

pottersheep · Answer

Try posting it in the chem section maybe?