Is y=1+(1/x)+(1/x^2) and odd or even function?
what does f(-a) equal?
y=f(x)=1+(1/x)+(1/x^2) Check for f(-x)
or if numbers are more your type does f(-2) = f(2)? or does f(-2) = -f(2)??
If @amistre64 1st condition gets proved its Even,If the 2nd condition gets proved its Odd,If your question does not satisfy the above conditions,Then its neither even nor odd.
I got it. Thanks.
or by analysis \[1+(1/x)+(1/x^2)=\frac{x^2+x+1}{x^2}\] these work like +- rules; even/even=even i believe
but then again, the top is not even since it is shifted from the y axis
Your'e welcome.
In some case if the power turns out to be even then the function is even,if the power is odd then the answer is odd. The trigonometric values also : sin (–x) = –sin x cos (–x) = cos x tan (–x) = –tan x csc (–x) = –csc x sec (–x) = sec x cot (–x) = –cot x
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