]Choose the equation of the line passing through the point (3, -2) and parallel to y = 3x - 6. y = 3x + 7 y = 3x - 11 y = -3x + 11 y = -3x - 12
since it's parallel, you can eliminate two of those choices. and of those two, plug in the point (3, -2) and see which one works...
how do you do that ?
first, do you know which two to eliminate from consideration?
no..
ok... in \(\large y=mx+b \), m is the slope of the line, and b is the y-intercept. in order for lines to be parallel, they must have the SAME slope..
what is the slope of the line?
hmmmm.... idk i'm all new to this. i'm sorry...
your line is written in what's called slope-intercept form: \(\huge y=mx+b \) the number in front of the "x" is the slope of the line. that's what "m" is.
this is your equation: y = 3x - 6 can you tell me what the slope is here?
m=3, b=-6 where m is the slope slope The steepness of a line expressed as a ratio, using any two points on the line. and b is the y-intercept y-intercept The value of y at the point where a curve crosses the y-axis.
ok... so the slope is 3, which of those choices have a slope of 3?
all of them ?..
be careful... there are only two with the SAME slope.
i'm not really sure.
what's the slope of the THIRD and LAST choice?
11 and 12 ?
@dpaInc
i was asking what is the SLOPE of the line in the third and last choices...
i'm still talking about the number in front of the "x", the slope....
3 and -3 ?
@dpaInc
ok... the third and fourth choices have a slope of -3. it is these two that you can eliminate from consideration because the slope you have is 3. so only consider the first two choices because they both have a slope of 3.
now, with the first two choices, plug in the point (3, -2) into each equation and see which one gives a true statement.
plug in (3, -2) into each equation you get: for the first choice: y = 3x + 7 -2 = 3(3) + 7 continue to simplify... for the second choice: y = 3x - 11 -2 = 3(3) - 11 continue to simplify... which one gives a true statement in the end?
i got it now! thank you so much for your time and help!!!!
no problem...:) glad u stuck with it.... which one gave a correct statement?
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