Question

i dont understand this could someone explain it to me

Answer 1

question number 34

Answer 2

@phi @hartnn

Answer 3

I think they want you to write the 6 different orders you can do the integration
they show the order y z x

the 6 different orders are
x y z
x z y
y x z
y z x <-- this one given
z x y
z y x

Answer 4

i get all of them except for the last two in the answer key
why did they do that split it into region 1 and 2 and how did they work out the answers

Answer 5

This was painful but here is my attempt at explaining how to find the limits for the order x,y,z (inner to outer). I could write up the x z y problem if you think it is necessary.

Answer 6

in the answer key they split the region differnetly why so?

Answer 7

I don't understand the question. I got the same limits as your answer key. See the bottom of the pdf and compare to your answer.

Answer 8

you split region one and two differently from the answer key theres is vertical yours is horizontal ..your i understand theres doesnt make any sense

Answer 9

In your answer (Box labeled Step 6 of 6), the 2nd line
it shows the limits in the left-hand integral are
0 ≤ x ≤ sqrt(1-z)
0 ≤ y ≤ 1- sqrt(1-z)
0 ≤ z ≤ 1

and the limits on the other integral are
0 ≤ x ≤ 1-y
1- sqrt(1-z)≤ y ≤ 1
0 ≤ z ≤ 1

Answer 10

If you are asking about their figure showing R1 and R2, I did not find it informative, or I should say, hard to visualize

Answer 11

no refer to the image their image is a square with a curve in it

Answer 12

yes im having a hard time visualizing the image ...so its not just me

Answer 13

yours is really the same thing though i i guess thats fine=)

Answer 14

It took me forever to find a "formula" for how to do these problems, and that is the best I could come up with. See if you can use the same ideas to find the limits for the order x z y

Answer 15

thanks yea the limits are
set one: 0<x<1-y , 0<z<2y-y^2 , 0<y<1
plus
set 2: 0<x<sqrt(1-z), 2y-y^2<z<1 and 0<y<1

Answer 16

thanks for your help=)