How do you evaluate sin(arctan -4/3)?
Find arctan of -4/3 first. Drawing the triangle on the unit circle is good for this.
I know how to solve for arctan positive 4/3 but I'm not sure how to solve it when it is negative.
tangent is opposite over adjacent, which means that to get -4/3, either the opposite side or the adjacent side must be negative. |dw:1353796505235:dw|
I think because of domain and range issues, you need to take the fourth quadrant angle.
Right. Only the triangle in the fourth quadrant need be considered because the inverse tangent function is defined over the interval\[\frac{ - \pi }{ 2 }<x <\frac{ \pi }{ 2 }\]
|dw:1353929353888:dw| By Pythagorean theorem the third side (hypotenuse side) is 5. Now what is the sine ratio of the angle the terminal arm forms with the x-axis? That ratio is your desired answer.
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