Question

Pre Calc:
If y varies inversely as the cube root of x, and y = 12 when x = 8, find y when x = 1.
y = ?
xoxo

Answer 1

\[y=\frac{k}{x^3}\]
put(8,12) then find k

Answer 2

after since you have k put x=1 to get y

Answer 3

@Jonask so y=12?

Answer 4

did you get k first

Answer 5

cube ROOT of x, might wanna fix that real quick @Jonask ! :D

Answer 6

yes\[y=\frac{ k }{\sqrt[3]{x} }\]
thanks @zepdrix

Answer 7

Ifound 12=k/8^3 (y=k/x^3 with substitutions) ~12=1644/8^3

Answer 8

@samalami the formular had mistake

Answer 9

ohhhhhh!

Answer 10

then k is 24

Answer 11

@Jonask ??

Answer 12

thanks for the clarification @zepdrix :)

Answer 13

k=24? yah that sounds right :D

Answer 14

so now find y when x=1\[y=\frac{24}{\sqrt[3]{1}}\]

Answer 15

y would equal 24 @Jonask

Answer 16

@zepdrix does this mean y=24 is the answer to the entire question?

Answer 17

Hmm yah that sounds right :D
Yayyy sammy! \c:/

Answer 18

@zepdrix much thanks! xoxo