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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the expression attached and write it as a single logarithm.. ***still confused on this topic... pls help? :)

OpenStudy (anonymous):

OpenStudy (anonymous):

answer choices A,B,C,D from top to bottom :)

OpenStudy (tkhunny):

Move all the exponents up: \((x+4)^{-3}\) \((x-7)^{2}\) \((x-2)^{5}\) \((x^{2})^{-1}\) Notice how I deliberately left everything outside as ADDITION. This allows us just to bring everything inside without concern for numerator or denominator. We can figure all that out later.

OpenStudy (anonymous):

im confused.. so how can i apply that with my expression?

OpenStudy (tkhunny):

Confused with what? \(-3\log(x+4) = \log\left[\left(x+4\right)^{-3}\right]\) Correct?

OpenStudy (anonymous):

im not quite sure what we are working on now.. I'm like uber confused.. are we doing my problem? or an example? :/ sorry I'm a bit confused :(

OpenStudy (tkhunny):

Your problem statement begins \(-3\log(x+4)\), doesn't it? Or am I looking at some other picture?

OpenStudy (anonymous):

yup iy does :) so i get log[(x+4)^−3] from that part?

OpenStudy (tkhunny):

Very good. Now the (x-7) part?

OpenStudy (anonymous):

2log(x-7) = log(x-7)^2 ??

OpenStudy (tkhunny):

Good, now the x-2...

OpenStudy (anonymous):

5log(x-2)=log(x-2)^5 ??

OpenStudy (tkhunny):

One more. You're on a roll!

OpenStudy (anonymous):

lol thanks haha :P but i don't get this one... it looks different.. :/ -logx^2...

OpenStudy (anonymous):

but heres my take on it.. log(x^2)^-1 ??

OpenStudy (tkhunny):

Take the negative (-1) inside, just like the other coefficients ==> exponents.

OpenStudy (anonymous):

was what i got right?? or no?

OpenStudy (anonymous):

or is it log(x)^-2 ?

OpenStudy (tkhunny):

There it is. They are now all connected by addition. Use this guy and bring them all together. log(a) + log(b) = log(a*b)

OpenStudy (anonymous):

sorry my computer crashed... one sec :/

OpenStudy (anonymous):

log[(x+4)^−3]+ log(x-2)^5+log(x-7)^2 + log(x)^-2=answer B right? :)

jimthompson5910 (jim_thompson5910):

use the rule described above to go from log[(x+4)^−3]+ log(x-2)^5+log(x-7)^2 + log(x)^-2 to log[ (x+4)^−3*(x-2)^5*(x-7)^2*(x)^-2 ]

OpenStudy (anonymous):

kk I'm seeing that :) but how can i simplify it even further?

jimthompson5910 (jim_thompson5910):

(x+4)^−3 is really 1/[ (x+4)^3 ]

jimthompson5910 (jim_thompson5910):

same idea applies to (x)^-2

OpenStudy (anonymous):

ok so i get 1/x^-2 ?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

so put that all together

OpenStudy (anonymous):

so i get answer C right?? :)

OpenStudy (anonymous):

sorry i meant answer D :) is it answer D then? :)

OpenStudy (anonymous):

@jim_thompson5910 :)

jimthompson5910 (jim_thompson5910):

yes it is D

OpenStudy (anonymous):

kk great!!! thx :)

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