\[\Huge \int x \sin (x) \text{d}x \]
@Callisto @CliffSedge Any idea?
I'd use integration by parts.
How? Sorry, I'm new to integral...
If you've never heard of integration by parts, then this is going to be a long lesson. Are you familiar with the product rule for differentiation?
Yes, I'm familiar with product rule.
I don't see what it has to do with integral, lol.
By the Fundamental Theorem of Calculus, integration is the inverse of differentiation. It would be the same as if you had a logarithm problem, and I asked if you knew how to handle exponents.
Integration by parts is derived from the product rule.
Wait... do you mean we have to "solve inversely" or something like this? I'm not sure what you mean.
Take (uv)' = uv' + vu' and rewrite as uv' = (uv)' - vu' and integrate both sides. You'll get \[\large \int\limits udv=uv-\int\limits vdu\]
In your example, let u=x and dv=sin(x)dx.
Can you get it from there, @geerky42 ?
Yes, I can. Thanks.
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