Question

If a/6 has a remainder of 5 and b/6 has a remainder of 4, then (a + b)/6 has a remainder of _________.

Answer 1

\[\frac{a+b}{6}=\frac{a}{6}+\frac{b}{6}\]

Answer 2

And?

I don't know rocket science.

Answer 3

result will b 3

Answer 4

a=11
b=10

Answer 5

a/6 has remainders 5 so the value of a will b 11

Answer 6

How did you get 11?

Answer 7

b/6 has remainders 4 so the value of b will b 10

Answer 8

6+5=11

Answer 9

Oh god,

Answer 10

I have no idea why you would even add them.

Answer 11

so (a+b)/6
=(11+10)/6
=21/6

Answer 12

it has remainder 3

Answer 13

Ouch, Please don't write down three.

Answer 14

jiji it's not saying there is a remainder of 5 the equation would look lik this

\[\frac{a}{6}+\frac{5}{6}+\frac{b}{6}+\frac{4}{6}\]

Answer 15

It IS saying there is a remainder of 5.

Answer 16

since when is a remaind a whole number ?

Answer 17

for example divide a polynomial by a smalller polynomial f(x). Do you just say the whole number as the remainder or do you say

\[\frac{a}{f(x)}\]

Answer 18

I think I'll wait for the answer.

Answer 19

if the remainder was just 5, there wouldn't be a remainder: it would divide evenly

Answer 20

Mhmm true.

Answer 21

I gave the biggest hint and i actually showed what it would be

Answer 22

a+5/6 then?

Answer 23

just never gave the exact

Answer 24

yes for the first... and then for the second

Answer 25

We'll let the guy who wrote this question do it ;)

Answer 26

so what you end up with is \[\frac{9}{6}=1+\frac{3}{6}\]

Answer 27

sorry

Answer 28

now what you get is

\[c_1+c_2+1+\frac{3}{6}\] where \[c_1,c_2 \] are whole

\[(c_1+c_2+1)+\frac{3}{6}\]