Question

show that 2^(n-1) - 2^(n-2) = 2^(n-2) . please show me the process thank you :)

Answer 1

\[2^{n-2}[2-1]=2^{n-2}\]

Answer 2

factor out 2^(n-2)...
\(\large 2^{n-1} - 2^{n-2} = 2^{n-2} \)
\(\large 2^{n-2}(2^1 - 1) = 2^{n-2} \)
\(\large 2^{n-2}(2 - 1) = 2^{n-2} \)

Answer 3

Take 2^{n-2} common outside!

Answer 4

\[2^{(n-1)}-2^{(n-2)}\]

Answer 5

\[or, 2^{n}/2-2^{n}/4\]

Answer 6

\[or, 2^{n}(1/2-1/4)\]

Answer 7

thank you so much for all the answers, understood it now ! really thank you ^^

Answer 8

\[2^{n}((2-1)/4\]

Answer 9

\[or, 2^{n}/4\]

Answer 10

\[or, 2^{n}/2^{2}\]

Answer 11

\[=2^{n-2}\]