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Chemistry 15 Online
OpenStudy (anonymous):

can someone please help me balance this reaction... equation in question below...

OpenStudy (anonymous):

\[NaOH + CO _{2} \rightarrow NaCO _{3} + H _{2}O\]

OpenStudy (anonymous):

where it is equation

OpenStudy (anonymous):

this is wrong

OpenStudy (anonymous):

thats how i got the question.... i think they made a mistake... do u agree that the NaCO3 should rather ne Na2CO3..???

OpenStudy (anonymous):

2Naoh +co2 --- na2co3 +h2o

OpenStudy (anonymous):

yeah i think so too... it must be a typo in the question they gave me

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

hey any question plz

OpenStudy (vincent-lyon.fr):

You can also have: \(NaOH + CO _{2} \rightarrow Na\color {red} HCO _{3}\)

OpenStudy (anonymous):

yaa thats also true

OpenStudy (anonymous):

yeah i know that but i had to balance the equation the way they gave it to me. but thank you both.

OpenStudy (vincent-lyon.fr):

Then there's a typo in the question, definitely.

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