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Mathematics 20 Online
OpenStudy (anonymous):

Finding a limit

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0} \frac{ \sqrt[5]{1+2x}-1 }{ \sin x }\]

OpenStudy (anonymous):

try l`hopital

OpenStudy (anonymous):

sorry, I forgot to mention that we haven't learnt about l`hopital

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

you learned Taylors series?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

expand the root term by binomial theorem

OpenStudy (anonymous):

then there will be term like 10x/sinx and x/sinx=1 for given condition so ans =10

OpenStudy (anonymous):

while opening with binomial neglect higher degree terms

OpenStudy (anonymous):

well, the answer should be 0.4 . And what do you mean by expanding the root term by binomial theorem? Do you mean, that I should raise the fraction by the 5th degree and then use the binomial theorem and numerator?

OpenStudy (anonymous):

no see it i have shown|dw:1353844296253:dw|

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