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Mathematics
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Finding a limit
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\[\lim_{x \rightarrow 0} \frac{ \sqrt[5]{1+2x}-1 }{ \sin x }\]
try l`hopital
sorry, I forgot to mention that we haven't learnt about l`hopital
nvm
you learned Taylors series?
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Nope
expand the root term by binomial theorem
then there will be term like 10x/sinx and x/sinx=1 for given condition so ans =10
while opening with binomial neglect higher degree terms
well, the answer should be 0.4 . And what do you mean by expanding the root term by binomial theorem? Do you mean, that I should raise the fraction by the 5th degree and then use the binomial theorem and numerator?
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no see it i have shown|dw:1353844296253:dw|
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