find the general term sequence fora^n for the geometric system. a1=-5 and a2=10
i tried to solve this equation a2=-5+(2-1)(10)
a geometric series is of the form a, ar , ar^2.. general term is ar^(n-1)
well it has a and the n is at the bottom instead at the top a^2 is wrong i cannot find the correct button for a/n i think its a[n]
for the term sequence a[n]
if a = a1 = -5 and a2 = -10 then can you figure out what r is?
* a2 = 10
well bellow i dont know if i set the problem up to start off solving below
i have a2=-5+(2-1)(10)
that is an arithmetic sequence general term a1 + (n - 1)d
that is correct
its confusing because you said its geometric
well the given set up is a[n]=a1+(n-1) d and it ask for general term of sequence
that is the general term for an AS a2 = -5 + (2 -1)d = -5 + d from this you can find the value of d , the common difference
i think d is 10 i am not sure
i got the answer a[n]=5
10 = -5 + d d = 15
a(n) = -5 + (n - 1)15
ok so you added 10+5=15
so for example a5 = -5 + (5-1)15 = -5 + 60 = 55
yes
a(n)=-5+(5-1)15
oh i see you have answered it
thank you for taking the time with me
a(n) = -5 + (n-1)15 is general form you just plug a value in for n - e.g. for 10th term you plug in n = 10
welcome
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